Metamath Proof Explorer


Theorem oa1un

Description: Given A e. On , let A +o 1o be defined to be the union of A and { A } . Compare with oa1suc . (Contributed by RP, 27-Sep-2023)

Ref Expression
Assertion oa1un ( 𝐴 ∈ On → ( 𝐴 +o 1o ) = ( 𝐴 ∪ { 𝐴 } ) )

Proof

Step Hyp Ref Expression
1 oa1suc ( 𝐴 ∈ On → ( 𝐴 +o 1o ) = suc 𝐴 )
2 df-suc suc 𝐴 = ( 𝐴 ∪ { 𝐴 } )
3 1 2 eqtrdi ( 𝐴 ∈ On → ( 𝐴 +o 1o ) = ( 𝐴 ∪ { 𝐴 } ) )