Metamath Proof Explorer


Theorem onlesd

Description: Less-than or equal is the same as non-strict birthday comparison over surreal ordinals. Deduction version. (Contributed by Scott Fenton, 25-Feb-2026)

Ref Expression
Hypotheses onltsd.1 ⊢ ( 𝜑 → 𝐴 ∈ Ons )
onltsd.2 ⊢ ( 𝜑 → 𝐵 ∈ Ons )
Assertion onlesd ( 𝜑 → ( 𝐴 ≤s 𝐵 ↔ ( bday ‘ 𝐴 ) ⊆ ( bday ‘ 𝐵 ) ) )

Proof

Step Hyp Ref Expression
1 onltsd.1 ⊢ ( 𝜑 → 𝐴 ∈ Ons )
2 onltsd.2 ⊢ ( 𝜑 → 𝐵 ∈ Ons )
3 onles ⊢ ( ( 𝐴 ∈ Ons ∧ 𝐵 ∈ Ons ) → ( 𝐴 ≤s 𝐵 ↔ ( bday ‘ 𝐴 ) ⊆ ( bday ‘ 𝐵 ) ) )
4 1 2 3 syl2anc ⊢ ( 𝜑 → ( 𝐴 ≤s 𝐵 ↔ ( bday ‘ 𝐴 ) ⊆ ( bday ‘ 𝐵 ) ) )