Metamath Proof Explorer


Theorem onlesd

Description: Less-than or equal is the same as non-strict birthday comparison over surreal ordinals. Deduction version. (Contributed by Scott Fenton, 25-Feb-2026)

Ref Expression
Hypotheses onltsd.1 ⊢ φ → A ∈ On s
onltsd.2 ⊢ φ → B ∈ On s
Assertion onlesd ⊢ φ → A ≤ s B ↔ bday ⁡ A ⊆ bday ⁡ B

Proof

Step Hyp Ref Expression
1 onltsd.1 ⊢ φ → A ∈ On s
2 onltsd.2 ⊢ φ → B ∈ On s
3 onles ⊢ A ∈ On s ∧ B ∈ On s → A ≤ s B ↔ bday ⁡ A ⊆ bday ⁡ B
4 1 2 3 syl2anc ⊢ φ → A ≤ s B ↔ bday ⁡ A ⊆ bday ⁡ B