Metamath Proof Explorer


Theorem onltsd

Description: Less-than is the same as birthday comparison over surreal ordinals. Deduction version. (Contributed by Scott Fenton, 25-Feb-2026)

Ref Expression
Hypotheses onltsd.1 ( 𝜑𝐴 ∈ Ons )
onltsd.2 ( 𝜑𝐵 ∈ Ons )
Assertion onltsd ( 𝜑 → ( 𝐴 <s 𝐵 ↔ ( bday 𝐴 ) ∈ ( bday 𝐵 ) ) )

Proof

Step Hyp Ref Expression
1 onltsd.1 ( 𝜑𝐴 ∈ Ons )
2 onltsd.2 ( 𝜑𝐵 ∈ Ons )
3 onlts ( ( 𝐴 ∈ Ons𝐵 ∈ Ons ) → ( 𝐴 <s 𝐵 ↔ ( bday 𝐴 ) ∈ ( bday 𝐵 ) ) )
4 1 2 3 syl2anc ( 𝜑 → ( 𝐴 <s 𝐵 ↔ ( bday 𝐴 ) ∈ ( bday 𝐵 ) ) )