Metamath Proof Explorer


Theorem opeq2i

Description: Equality inference for ordered pairs. (Contributed by NM, 16-Dec-2006)

Ref Expression
Hypothesis opeq1i.1 ⊢ 𝐴 = 𝐵
Assertion opeq2i ⟨ 𝐶 , 𝐴 ⟩ = ⟨ 𝐶 , 𝐵 ⟩

Proof

Step Hyp Ref Expression
1 opeq1i.1 ⊢ 𝐴 = 𝐵
2 opeq2 ⊢ ( 𝐴 = 𝐵 → ⟨ 𝐶 , 𝐴 ⟩ = ⟨ 𝐶 , 𝐵 ⟩ )
3 1 2 ax-mp ⊢ ⟨ 𝐶 , 𝐴 ⟩ = ⟨ 𝐶 , 𝐵 ⟩