Metamath Proof Explorer


Theorem opnneibid

Description: The equivalence between neighborhood and open neighborhood. See opnneibid2 for different dummy variables. (Contributed by Zhi Wang, 31-Aug-2024)

Ref Expression
Hypotheses opnneir.1 ⊢ ( 𝜑 → 𝐽 ∈ Top )
opnneilv.2 ⊢ ( ( 𝜑 ∧ 𝑦 ⊆ 𝑥 ) → ( 𝜓 → 𝜒 ) )
opnneil.3 ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → ( 𝜓 ↔ 𝜒 ) )
Assertion opnneibid ( 𝜑 → ( ∃ 𝑥 ∈ ( ( nei ‘ 𝐽 ) ‘ 𝑆 ) 𝜓 ↔ ∃ 𝑥 ∈ 𝐽 ( 𝑆 ⊆ 𝑥 ∧ 𝜓 ) ) )

Proof

Step Hyp Ref Expression
1 opnneir.1 ⊢ ( 𝜑 → 𝐽 ∈ Top )
2 opnneilv.2 ⊢ ( ( 𝜑 ∧ 𝑦 ⊆ 𝑥 ) → ( 𝜓 → 𝜒 ) )
3 opnneil.3 ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → ( 𝜓 ↔ 𝜒 ) )
4 1 2 3 opnneil ⊢ ( 𝜑 → ( ∃ 𝑥 ∈ ( ( nei ‘ 𝐽 ) ‘ 𝑆 ) 𝜓 → ∃ 𝑥 ∈ 𝐽 ( 𝑆 ⊆ 𝑥 ∧ 𝜓 ) ) )
5 1 opnneir ⊢ ( 𝜑 → ( ∃ 𝑥 ∈ 𝐽 ( 𝑆 ⊆ 𝑥 ∧ 𝜓 ) → ∃ 𝑥 ∈ ( ( nei ‘ 𝐽 ) ‘ 𝑆 ) 𝜓 ) )
6 4 5 impbid ⊢ ( 𝜑 → ( ∃ 𝑥 ∈ ( ( nei ‘ 𝐽 ) ‘ 𝑆 ) 𝜓 ↔ ∃ 𝑥 ∈ 𝐽 ( 𝑆 ⊆ 𝑥 ∧ 𝜓 ) ) )