Metamath Proof Explorer


Theorem oppggic

Description: Every group is (naturally) isomorphic to its opposite. (Contributed by Stefan O'Rear, 26-Aug-2015)

Ref Expression
Hypothesis oppggic.o ⊢ 𝑂 = ( oppg ‘ 𝐺 )
Assertion oppggic ( 𝐺 ∈ Grp → 𝐺 ≃𝑔 𝑂 )

Proof

Step Hyp Ref Expression
1 oppggic.o ⊢ 𝑂 = ( oppg ‘ 𝐺 )
2 eqid ⊢ ( invg ‘ 𝐺 ) = ( invg ‘ 𝐺 )
3 1 2 invoppggim ⊢ ( 𝐺 ∈ Grp → ( invg ‘ 𝐺 ) ∈ ( 𝐺 GrpIso 𝑂 ) )
4 brgici ⊢ ( ( invg ‘ 𝐺 ) ∈ ( 𝐺 GrpIso 𝑂 ) → 𝐺 ≃𝑔 𝑂 )
5 3 4 syl ⊢ ( 𝐺 ∈ Grp → 𝐺 ≃𝑔 𝑂 )