Metamath Proof Explorer


Theorem oran

Description: Disjunction in terms of conjunction (De Morgan's law). Compare Theorem *4.57 of WhiteheadRussell p. 120. (Contributed by NM, 3-Jan-1993) (Proof shortened by Andrew Salmon, 7-May-2011)

Ref Expression
Assertion oran ( ( 𝜑𝜓 ) ↔ ¬ ( ¬ 𝜑 ∧ ¬ 𝜓 ) )

Proof

Step Hyp Ref Expression
1 pm4.56 ( ( ¬ 𝜑 ∧ ¬ 𝜓 ) ↔ ¬ ( 𝜑𝜓 ) )
2 1 con2bii ( ( 𝜑𝜓 ) ↔ ¬ ( ¬ 𝜑 ∧ ¬ 𝜓 ) )