Metamath Proof Explorer


Theorem ordsson

Description: Any ordinal class is a subclass of the class of ordinal numbers. Corollary 7.15 of TakeutiZaring p. 38. (Contributed by NM, 18-May-1994) (Proof shortened by Andrew Salmon, 12-Aug-2011)

Ref Expression
Assertion ordsson ( Ord 𝐴 → 𝐴 ⊆ On )

Proof

Step Hyp Ref Expression
1 ordon ⊢ Ord On
2 ordeleqon ⊢ ( Ord 𝐴 ↔ ( 𝐴 ∈ On ∨ 𝐴 = On ) )
3 2 birani ⊢ ( ( Ord 𝐴 ∧ Ord On ) → ( 𝐴 ∈ On ∨ 𝐴 = On ) )
4 ordsseleq ⊢ ( ( Ord 𝐴 ∧ Ord On ) → ( 𝐴 ⊆ On ↔ ( 𝐴 ∈ On ∨ 𝐴 = On ) ) )
5 3 4 mpbird ⊢ ( ( Ord 𝐴 ∧ Ord On ) → 𝐴 ⊆ On )
6 1 5 mpan2 ⊢ ( Ord 𝐴 → 𝐴 ⊆ On )