Metamath Proof Explorer


Theorem orim1i

Description: Introduce disjunct to both sides of an implication. (Contributed by NM, 6-Jun-1994)

Ref Expression
Hypothesis orim1i.1 ⊢ ( 𝜑 → 𝜓 )
Assertion orim1i ( ( 𝜑 ∨ 𝜒 ) → ( 𝜓 ∨ 𝜒 ) )

Proof

Step Hyp Ref Expression
1 orim1i.1 ⊢ ( 𝜑 → 𝜓 )
2 id ⊢ ( 𝜒 → 𝜒 )
3 1 2 orim12i ⊢ ( ( 𝜑 ∨ 𝜒 ) → ( 𝜓 ∨ 𝜒 ) )