Metamath Proof Explorer


Theorem oveq12d

Description: Equality deduction for operation value. (Contributed by NM, 13-Mar-1995) (Proof shortened by Andrew Salmon, 22-Oct-2011)

Ref Expression
Hypotheses oveq1d.1 ( 𝜑𝐴 = 𝐵 )
oveq12d.2 ( 𝜑𝐶 = 𝐷 )
Assertion oveq12d ( 𝜑 → ( 𝐴 𝐹 𝐶 ) = ( 𝐵 𝐹 𝐷 ) )

Proof

Step Hyp Ref Expression
1 oveq1d.1 ( 𝜑𝐴 = 𝐵 )
2 oveq12d.2 ( 𝜑𝐶 = 𝐷 )
3 oveq12 ( ( 𝐴 = 𝐵𝐶 = 𝐷 ) → ( 𝐴 𝐹 𝐶 ) = ( 𝐵 𝐹 𝐷 ) )
4 1 2 3 syl2anc ( 𝜑 → ( 𝐴 𝐹 𝐶 ) = ( 𝐵 𝐹 𝐷 ) )