Metamath Proof Explorer
Description: Deduction converting a biconditional to a biconditional with
conjunction. Variant of pm4.71d . (Contributed by Zhi Wang, 30-Aug-2024)
|
|
Ref |
Expression |
|
Hypothesis |
pm4.71da.1 |
⊢ ( 𝜑 → ( 𝜓 ↔ 𝜒 ) ) |
|
Assertion |
pm4.71da |
⊢ ( 𝜑 → ( 𝜓 ↔ ( 𝜓 ∧ 𝜒 ) ) ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
pm4.71da.1 |
⊢ ( 𝜑 → ( 𝜓 ↔ 𝜒 ) ) |
2 |
1
|
biimpd |
⊢ ( 𝜑 → ( 𝜓 → 𝜒 ) ) |
3 |
2
|
pm4.71d |
⊢ ( 𝜑 → ( 𝜓 ↔ ( 𝜓 ∧ 𝜒 ) ) ) |