Metamath Proof Explorer


Theorem pssdif

Description: A proper subclass has a nonempty difference. (Contributed by Mario Carneiro, 27-Apr-2016)

Ref Expression
Assertion pssdif ( 𝐴 ⊊ 𝐵 → ( 𝐵 ∖ 𝐴 ) ≠ ∅ )

Proof

Step Hyp Ref Expression
1 df-pss ⊢ ( 𝐴 ⊊ 𝐵 ↔ ( 𝐴 ⊆ 𝐵 ∧ 𝐴 ≠ 𝐵 ) )
2 pssdifn0 ⊢ ( ( 𝐴 ⊆ 𝐵 ∧ 𝐴 ≠ 𝐵 ) → ( 𝐵 ∖ 𝐴 ) ≠ ∅ )
3 1 2 sylbi ⊢ ( 𝐴 ⊊ 𝐵 → ( 𝐵 ∖ 𝐴 ) ≠ ∅ )