Metamath Proof Explorer


Theorem pssss

Description: A proper subclass is a subclass. Theorem 10 of Suppes p. 23. (Contributed by NM, 7-Feb-1996)

Ref Expression
Assertion pssss ( 𝐴 ⊊ 𝐵 → 𝐴 ⊆ 𝐵 )

Proof

Step Hyp Ref Expression
1 df-pss ⊢ ( 𝐴 ⊊ 𝐵 ↔ ( 𝐴 ⊆ 𝐵 ∧ 𝐴 ≠ 𝐵 ) )
2 1 simplbi ⊢ ( 𝐴 ⊊ 𝐵 → 𝐴 ⊆ 𝐵 )