| Step |
Hyp |
Ref |
Expression |
| 1 |
|
df-qs |
⊢ ( dom 𝑅 / 𝑅 ) = { 𝑢 ∣ ∃ 𝑡 ∈ dom 𝑅 𝑢 = [ 𝑡 ] 𝑅 } |
| 2 |
1
|
eqabri |
⊢ ( 𝑢 ∈ ( dom 𝑅 / 𝑅 ) ↔ ∃ 𝑡 ∈ dom 𝑅 𝑢 = [ 𝑡 ] 𝑅 ) |
| 3 |
2
|
biimpi |
⊢ ( 𝑢 ∈ ( dom 𝑅 / 𝑅 ) → ∃ 𝑡 ∈ dom 𝑅 𝑢 = [ 𝑡 ] 𝑅 ) |
| 4 |
3
|
biantrurd |
⊢ ( 𝑢 ∈ ( dom 𝑅 / 𝑅 ) → ( ∃* 𝑡 ∈ dom 𝑅 𝑢 = [ 𝑡 ] 𝑅 ↔ ( ∃ 𝑡 ∈ dom 𝑅 𝑢 = [ 𝑡 ] 𝑅 ∧ ∃* 𝑡 ∈ dom 𝑅 𝑢 = [ 𝑡 ] 𝑅 ) ) ) |
| 5 |
|
reu5 |
⊢ ( ∃! 𝑡 ∈ dom 𝑅 𝑢 = [ 𝑡 ] 𝑅 ↔ ( ∃ 𝑡 ∈ dom 𝑅 𝑢 = [ 𝑡 ] 𝑅 ∧ ∃* 𝑡 ∈ dom 𝑅 𝑢 = [ 𝑡 ] 𝑅 ) ) |
| 6 |
4 5
|
bitr4di |
⊢ ( 𝑢 ∈ ( dom 𝑅 / 𝑅 ) → ( ∃* 𝑡 ∈ dom 𝑅 𝑢 = [ 𝑡 ] 𝑅 ↔ ∃! 𝑡 ∈ dom 𝑅 𝑢 = [ 𝑡 ] 𝑅 ) ) |
| 7 |
6
|
ralbiia |
⊢ ( ∀ 𝑢 ∈ ( dom 𝑅 / 𝑅 ) ∃* 𝑡 ∈ dom 𝑅 𝑢 = [ 𝑡 ] 𝑅 ↔ ∀ 𝑢 ∈ ( dom 𝑅 / 𝑅 ) ∃! 𝑡 ∈ dom 𝑅 𝑢 = [ 𝑡 ] 𝑅 ) |