Metamath Proof Explorer


Theorem reqabi

Description: Inference from equality of a class variable and a restricted class abstraction. (Contributed by NM, 16-Feb-2004)

Ref Expression
Hypothesis reqabi.1 ⊢ 𝐴 = { 𝑥 ∈ 𝐵 ∣ 𝜑 }
Assertion reqabi ( 𝑥 ∈ 𝐴 ↔ ( 𝑥 ∈ 𝐵 ∧ 𝜑 ) )

Proof

Step Hyp Ref Expression
1 reqabi.1 ⊢ 𝐴 = { 𝑥 ∈ 𝐵 ∣ 𝜑 }
2 1 eleq2i ⊢ ( 𝑥 ∈ 𝐴 ↔ 𝑥 ∈ { 𝑥 ∈ 𝐵 ∣ 𝜑 } )
3 rabid ⊢ ( 𝑥 ∈ { 𝑥 ∈ 𝐵 ∣ 𝜑 } ↔ ( 𝑥 ∈ 𝐵 ∧ 𝜑 ) )
4 2 3 bitri ⊢ ( 𝑥 ∈ 𝐴 ↔ ( 𝑥 ∈ 𝐵 ∧ 𝜑 ) )