Metamath Proof Explorer


Theorem resqcld

Description: Closure of squaring in reals, deduction form. (Contributed by Mario Carneiro, 28-May-2016)

Ref Expression
Hypothesis resqcld.1 ⊢ ( 𝜑 → 𝐴 ∈ ℝ )
Assertion resqcld ( 𝜑 → ( 𝐴 ↑ 2 ) ∈ ℝ )

Proof

Step Hyp Ref Expression
1 resqcld.1 ⊢ ( 𝜑 → 𝐴 ∈ ℝ )
2 resqcl ⊢ ( 𝐴 ∈ ℝ → ( 𝐴 ↑ 2 ) ∈ ℝ )
3 1 2 syl ⊢ ( 𝜑 → ( 𝐴 ↑ 2 ) ∈ ℝ )