Metamath Proof Explorer


Theorem right0s

Description: The right set of 0s is empty. (Contributed by Scott Fenton, 20-Aug-2024)

Ref Expression
Assertion right0s ( R ‘ 0s ) = ∅

Proof

Step Hyp Ref Expression
1 0sno 0s ∈ No
2 rightssold ( 0s ∈ No → ( R ‘ 0s ) ⊆ ( O ‘ ( bday ‘ 0s ) ) )
3 1 2 ax-mp ( R ‘ 0s ) ⊆ ( O ‘ ( bday ‘ 0s ) )
4 bday0s ( bday ‘ 0s ) = ∅
5 4 fveq2i ( O ‘ ( bday ‘ 0s ) ) = ( O ‘ ∅ )
6 old0 ( O ‘ ∅ ) = ∅
7 5 6 eqtri ( O ‘ ( bday ‘ 0s ) ) = ∅
8 sseq0 ( ( ( R ‘ 0s ) ⊆ ( O ‘ ( bday ‘ 0s ) ) ∧ ( O ‘ ( bday ‘ 0s ) ) = ∅ ) → ( R ‘ 0s ) = ∅ )
9 3 7 8 mp2an ( R ‘ 0s ) = ∅