Metamath Proof Explorer
		
		
		
		Description:  A subclass of an empty class is empty.  (Contributed by NM, 7-Mar-2007)
     (Proof shortened by Andrew Salmon, 26-Jun-2011)
		
			
				
					 | 
					 | 
					Ref | 
					Expression | 
				
				
					 | 
					Assertion | 
					sseq0 | 
					⊢  ( ( 𝐴  ⊆  𝐵  ∧  𝐵  =  ∅ )  →  𝐴  =  ∅ )  | 
				
			
		
		
			
				Proof
				
					
						| Step | 
						Hyp | 
						Ref | 
						Expression | 
					
						
							| 1 | 
							
								
							 | 
							sseq2 | 
							⊢ ( 𝐵  =  ∅  →  ( 𝐴  ⊆  𝐵  ↔  𝐴  ⊆  ∅ ) )  | 
						
						
							| 2 | 
							
								
							 | 
							ss0 | 
							⊢ ( 𝐴  ⊆  ∅  →  𝐴  =  ∅ )  | 
						
						
							| 3 | 
							
								1 2
							 | 
							biimtrdi | 
							⊢ ( 𝐵  =  ∅  →  ( 𝐴  ⊆  𝐵  →  𝐴  =  ∅ ) )  | 
						
						
							| 4 | 
							
								3
							 | 
							impcom | 
							⊢ ( ( 𝐴  ⊆  𝐵  ∧  𝐵  =  ∅ )  →  𝐴  =  ∅ )  |