Metamath Proof Explorer


Theorem rlmmulr

Description: Ring multiplication in the ring module. (Contributed by Mario Carneiro, 6-Oct-2015)

Ref Expression
Assertion rlmmulr ( .r ‘ 𝑅 ) = ( .r ‘ ( ringLMod ‘ 𝑅 ) )

Proof

Step Hyp Ref Expression
1 rlmval ⊢ ( ringLMod ‘ 𝑅 ) = ( ( subringAlg ‘ 𝑅 ) ‘ ( Base ‘ 𝑅 ) )
2 1 a1i ⊢ ( ⊤ → ( ringLMod ‘ 𝑅 ) = ( ( subringAlg ‘ 𝑅 ) ‘ ( Base ‘ 𝑅 ) ) )
3 ssidd ⊢ ( ⊤ → ( Base ‘ 𝑅 ) ⊆ ( Base ‘ 𝑅 ) )
4 2 3 sramulr ⊢ ( ⊤ → ( .r ‘ 𝑅 ) = ( .r ‘ ( ringLMod ‘ 𝑅 ) ) )
5 4 mptru ⊢ ( .r ‘ 𝑅 ) = ( .r ‘ ( ringLMod ‘ 𝑅 ) )