Metamath Proof Explorer


Theorem rneqi

Description: Equality inference for range. (Contributed by NM, 4-Mar-2004)

Ref Expression
Hypothesis rneqi.1 𝐴 = 𝐵
Assertion rneqi ran 𝐴 = ran 𝐵

Proof

Step Hyp Ref Expression
1 rneqi.1 𝐴 = 𝐵
2 rneq ( 𝐴 = 𝐵 → ran 𝐴 = ran 𝐵 )
3 1 2 ax-mp ran 𝐴 = ran 𝐵