Metamath Proof Explorer


Theorem rneqi

Description: Equality inference for range. (Contributed by NM, 4-Mar-2004)

Ref Expression
Hypothesis rneqi.1 ⊢ A = B
Assertion rneqi ⊢ ran ⁡ A = ran ⁡ B

Proof

Step Hyp Ref Expression
1 rneqi.1 ⊢ A = B
2 rneq ⊢ A = B → ran ⁡ A = ran ⁡ B
3 1 2 ax-mp ⊢ ran ⁡ A = ran ⁡ B