Metamath Proof Explorer


Theorem rngen1zr0

Description: The only ring with one element is the zero ring (at least if its operations are internal binary operations). (Contributed by FL, 15-Feb-2010) (Revised by AV, 18-Jun-2026)

Ref Expression
Hypotheses rng1zr.b 𝐵 = ( Base ‘ 𝑅 )
rng1zr.p + = ( +g𝑅 )
rng1zr.t = ( .r𝑅 )
rngen1zr0.0 0 = ( 0g𝑅 )
Assertion rngen1zr0 ( ( 𝑅 ∈ Rng ∧ + Fn ( 𝐵 × 𝐵 ) ∧ Fn ( 𝐵 × 𝐵 ) ) → ( 𝐵 ≈ 1o ↔ ( + = { ⟨ ⟨ 0 , 0 ⟩ , 0 ⟩ } ∧ = { ⟨ ⟨ 0 , 0 ⟩ , 0 ⟩ } ) ) )

Proof

Step Hyp Ref Expression
1 rng1zr.b 𝐵 = ( Base ‘ 𝑅 )
2 rng1zr.p + = ( +g𝑅 )
3 rng1zr.t = ( .r𝑅 )
4 rngen1zr0.0 0 = ( 0g𝑅 )
5 1 4 rng0cl ( 𝑅 ∈ Rng → 0𝐵 )
6 5 3ad2ant1 ( ( 𝑅 ∈ Rng ∧ + Fn ( 𝐵 × 𝐵 ) ∧ Fn ( 𝐵 × 𝐵 ) ) → 0𝐵 )
7 1 2 3 rngen1zr ( ( ( 𝑅 ∈ Rng ∧ + Fn ( 𝐵 × 𝐵 ) ∧ Fn ( 𝐵 × 𝐵 ) ) ∧ 0𝐵 ) → ( 𝐵 ≈ 1o ↔ ( + = { ⟨ ⟨ 0 , 0 ⟩ , 0 ⟩ } ∧ = { ⟨ ⟨ 0 , 0 ⟩ , 0 ⟩ } ) ) )
8 6 7 mpdan ( ( 𝑅 ∈ Rng ∧ + Fn ( 𝐵 × 𝐵 ) ∧ Fn ( 𝐵 × 𝐵 ) ) → ( 𝐵 ≈ 1o ↔ ( + = { ⟨ ⟨ 0 , 0 ⟩ , 0 ⟩ } ∧ = { ⟨ ⟨ 0 , 0 ⟩ , 0 ⟩ } ) ) )