Metamath Proof Explorer


Theorem rngoiso1o

Description: Obsolete theorem, use rimf1o instead. A ring isomorphism is a bijection. (Contributed by Jeff Madsen, 16-Jun-2011) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Hypotheses rngisoval.1 ⊢ 𝐺 = ( 1st ‘ 𝑅 )
rngisoval.2 ⊢ 𝑋 = ran 𝐺
rngisoval.3 ⊢ 𝐽 = ( 1st ‘ 𝑆 )
rngisoval.4 ⊢ 𝑌 = ran 𝐽
Assertion rngoiso1o ( ( 𝑅 ∈ RingOps ∧ 𝑆 ∈ RingOps ∧ 𝐹 ∈ ( 𝑅 RingOpsIso 𝑆 ) ) → 𝐹 : 𝑋 –1-1-onto→ 𝑌 )

Proof

Step Hyp Ref Expression
1 rngisoval.1 ⊢ 𝐺 = ( 1st ‘ 𝑅 )
2 rngisoval.2 ⊢ 𝑋 = ran 𝐺
3 rngisoval.3 ⊢ 𝐽 = ( 1st ‘ 𝑆 )
4 rngisoval.4 ⊢ 𝑌 = ran 𝐽
5 1 2 3 4 isrngoiso ⊢ ( ( 𝑅 ∈ RingOps ∧ 𝑆 ∈ RingOps ) → ( 𝐹 ∈ ( 𝑅 RingOpsIso 𝑆 ) ↔ ( 𝐹 ∈ ( 𝑅 RingOpsHom 𝑆 ) ∧ 𝐹 : 𝑋 –1-1-onto→ 𝑌 ) ) )
6 5 simplbda ⊢ ( ( ( 𝑅 ∈ RingOps ∧ 𝑆 ∈ RingOps ) ∧ 𝐹 ∈ ( 𝑅 RingOpsIso 𝑆 ) ) → 𝐹 : 𝑋 –1-1-onto→ 𝑌 )
7 6 3impa ⊢ ( ( 𝑅 ∈ RingOps ∧ 𝑆 ∈ RingOps ∧ 𝐹 ∈ ( 𝑅 RingOpsIso 𝑆 ) ) → 𝐹 : 𝑋 –1-1-onto→ 𝑌 )