Metamath Proof Explorer


Theorem rrgss

Description: Left-regular elements are a subset of the base set. (Contributed by Stefan O'Rear, 22-Mar-2015)

Ref Expression
Hypotheses rrgss.e ⊢ 𝐸 = ( RLReg ‘ 𝑅 )
rrgss.b ⊢ 𝐵 = ( Base ‘ 𝑅 )
Assertion rrgss 𝐸 ⊆ 𝐵

Proof

Step Hyp Ref Expression
1 rrgss.e ⊢ 𝐸 = ( RLReg ‘ 𝑅 )
2 rrgss.b ⊢ 𝐵 = ( Base ‘ 𝑅 )
3 eqid ⊢ ( .r ‘ 𝑅 ) = ( .r ‘ 𝑅 )
4 eqid ⊢ ( 0g ‘ 𝑅 ) = ( 0g ‘ 𝑅 )
5 1 2 3 4 rrgval ⊢ 𝐸 = { 𝑥 ∈ 𝐵 ∣ ∀ 𝑦 ∈ 𝐵 ( ( 𝑥 ( .r ‘ 𝑅 ) 𝑦 ) = ( 0g ‘ 𝑅 ) → 𝑦 = ( 0g ‘ 𝑅 ) ) }
6 5 ssrab3 ⊢ 𝐸 ⊆ 𝐵