Metamath Proof Explorer


Theorem rru

Description: Relative version of Russell's paradox ru (which corresponds to the case A = _V ).

Originally a subproof in pwnss . (Contributed by Stefan O'Rear, 22-Feb-2015) Avoid df-nel . (Revised by Steven Nguyen, 23-Nov-2022) Reduce axiom usage. (Revised by GG, 30-Aug-2024)

Ref Expression
Assertion rru ¬ { 𝑥 ∈ 𝐴 ∣ ¬ 𝑥 ∈ 𝑥 } ∈ 𝐴

Proof

Step Hyp Ref Expression
1 eleq12 ⊢ ( ( 𝑦 = { 𝑥 ∈ 𝐴 ∣ ¬ 𝑥 ∈ 𝑥 } ∧ 𝑦 = { 𝑥 ∈ 𝐴 ∣ ¬ 𝑥 ∈ 𝑥 } ) → ( 𝑦 ∈ 𝑦 ↔ { 𝑥 ∈ 𝐴 ∣ ¬ 𝑥 ∈ 𝑥 } ∈ { 𝑥 ∈ 𝐴 ∣ ¬ 𝑥 ∈ 𝑥 } ) )
2 1 anidms ⊢ ( 𝑦 = { 𝑥 ∈ 𝐴 ∣ ¬ 𝑥 ∈ 𝑥 } → ( 𝑦 ∈ 𝑦 ↔ { 𝑥 ∈ 𝐴 ∣ ¬ 𝑥 ∈ 𝑥 } ∈ { 𝑥 ∈ 𝐴 ∣ ¬ 𝑥 ∈ 𝑥 } ) )
3 2 notbid ⊢ ( 𝑦 = { 𝑥 ∈ 𝐴 ∣ ¬ 𝑥 ∈ 𝑥 } → ( ¬ 𝑦 ∈ 𝑦 ↔ ¬ { 𝑥 ∈ 𝐴 ∣ ¬ 𝑥 ∈ 𝑥 } ∈ { 𝑥 ∈ 𝐴 ∣ ¬ 𝑥 ∈ 𝑥 } ) )
4 eleq12 ⊢ ( ( 𝑥 = 𝑦 ∧ 𝑥 = 𝑦 ) → ( 𝑥 ∈ 𝑥 ↔ 𝑦 ∈ 𝑦 ) )
5 4 anidms ⊢ ( 𝑥 = 𝑦 → ( 𝑥 ∈ 𝑥 ↔ 𝑦 ∈ 𝑦 ) )
6 5 notbid ⊢ ( 𝑥 = 𝑦 → ( ¬ 𝑥 ∈ 𝑥 ↔ ¬ 𝑦 ∈ 𝑦 ) )
7 6 cbvrabv ⊢ { 𝑥 ∈ 𝐴 ∣ ¬ 𝑥 ∈ 𝑥 } = { 𝑦 ∈ 𝐴 ∣ ¬ 𝑦 ∈ 𝑦 }
8 3 7 elrab2 ⊢ ( { 𝑥 ∈ 𝐴 ∣ ¬ 𝑥 ∈ 𝑥 } ∈ { 𝑥 ∈ 𝐴 ∣ ¬ 𝑥 ∈ 𝑥 } ↔ ( { 𝑥 ∈ 𝐴 ∣ ¬ 𝑥 ∈ 𝑥 } ∈ 𝐴 ∧ ¬ { 𝑥 ∈ 𝐴 ∣ ¬ 𝑥 ∈ 𝑥 } ∈ { 𝑥 ∈ 𝐴 ∣ ¬ 𝑥 ∈ 𝑥 } ) )
9 pclem6 ⊢ ( ( { 𝑥 ∈ 𝐴 ∣ ¬ 𝑥 ∈ 𝑥 } ∈ { 𝑥 ∈ 𝐴 ∣ ¬ 𝑥 ∈ 𝑥 } ↔ ( { 𝑥 ∈ 𝐴 ∣ ¬ 𝑥 ∈ 𝑥 } ∈ 𝐴 ∧ ¬ { 𝑥 ∈ 𝐴 ∣ ¬ 𝑥 ∈ 𝑥 } ∈ { 𝑥 ∈ 𝐴 ∣ ¬ 𝑥 ∈ 𝑥 } ) ) → ¬ { 𝑥 ∈ 𝐴 ∣ ¬ 𝑥 ∈ 𝑥 } ∈ 𝐴 )
10 8 9 ax-mp ⊢ ¬ { 𝑥 ∈ 𝐴 ∣ ¬ 𝑥 ∈ 𝑥 } ∈ 𝐴