Metamath Proof Explorer
		
		
		
		Description:  Restricted specialization, using implicit substitution.  (Contributed by Thierry Arnoux, 21-Jun-2020)
		
			
				
					|  |  | Ref | Expression | 
					
						|  | Hypotheses | rspcdva.1 | ⊢ ( 𝑥  =  𝐶  →  ( 𝜓  ↔  𝜒 ) ) | 
					
						|  |  | rspcdva.2 | ⊢ ( 𝜑  →  ∀ 𝑥  ∈  𝐴 𝜓 ) | 
					
						|  |  | rspcdva.3 | ⊢ ( 𝜑  →  𝐶  ∈  𝐴 ) | 
				
					|  | Assertion | rspcdva | ⊢  ( 𝜑  →  𝜒 ) | 
			
		
		
			
				Proof
				
					
						| Step | Hyp | Ref | Expression | 
						
							| 1 |  | rspcdva.1 | ⊢ ( 𝑥  =  𝐶  →  ( 𝜓  ↔  𝜒 ) ) | 
						
							| 2 |  | rspcdva.2 | ⊢ ( 𝜑  →  ∀ 𝑥  ∈  𝐴 𝜓 ) | 
						
							| 3 |  | rspcdva.3 | ⊢ ( 𝜑  →  𝐶  ∈  𝐴 ) | 
						
							| 4 | 1 | rspcv | ⊢ ( 𝐶  ∈  𝐴  →  ( ∀ 𝑥  ∈  𝐴 𝜓  →  𝜒 ) ) | 
						
							| 5 | 3 2 4 | sylc | ⊢ ( 𝜑  →  𝜒 ) |