Metamath Proof Explorer


Theorem rspcv

Description: Restricted specialization, using implicit substitution. (Contributed by NM, 26-May-1998) Drop ax-10 , ax-11 , ax-12 . (Revised by SN, 12-Dec-2023)

Ref Expression
Hypothesis rspcv.1 ⊢ ( 𝑥 = 𝐴 → ( 𝜑 ↔ 𝜓 ) )
Assertion rspcv ( 𝐴 ∈ 𝐵 → ( ∀ 𝑥 ∈ 𝐵 𝜑 → 𝜓 ) )

Proof

Step Hyp Ref Expression
1 rspcv.1 ⊢ ( 𝑥 = 𝐴 → ( 𝜑 ↔ 𝜓 ) )
2 id ⊢ ( 𝐴 ∈ 𝐵 → 𝐴 ∈ 𝐵 )
3 1 adantl ⊢ ( ( 𝐴 ∈ 𝐵 ∧ 𝑥 = 𝐴 ) → ( 𝜑 ↔ 𝜓 ) )
4 2 3 rspcdv ⊢ ( 𝐴 ∈ 𝐵 → ( ∀ 𝑥 ∈ 𝐵 𝜑 → 𝜓 ) )