Metamath Proof Explorer


Theorem rspcv

Description: Restricted specialization, using implicit substitution. (Contributed by NM, 26-May-1998) Drop ax-10 , ax-11 , ax-12 . (Revised by SN, 12-Dec-2023)

Ref Expression
Hypothesis rspcv.1 ⊢ x = A → φ ↔ ψ
Assertion rspcv ⊢ A ∈ B → ∀ x ∈ B φ → ψ

Proof

Step Hyp Ref Expression
1 rspcv.1 ⊢ x = A → φ ↔ ψ
2 id ⊢ A ∈ B → A ∈ B
3 1 adantl ⊢ A ∈ B ∧ x = A → φ ↔ ψ
4 2 3 rspcdv ⊢ A ∈ B → ∀ x ∈ B φ → ψ