Metamath Proof Explorer


Theorem rspccv

Description: Restricted specialization, using implicit substitution. (Contributed by NM, 2-Feb-2006)

Ref Expression
Hypothesis rspcv.1 ⊢ x = A → φ ↔ ψ
Assertion rspccv ⊢ ∀ x ∈ B φ → A ∈ B → ψ

Proof

Step Hyp Ref Expression
1 rspcv.1 ⊢ x = A → φ ↔ ψ
2 1 rspcv ⊢ A ∈ B → ∀ x ∈ B φ → ψ
3 2 com12 ⊢ ∀ x ∈ B φ → A ∈ B → ψ