Metamath Proof Explorer


Theorem rspcva

Description: Restricted specialization, using implicit substitution. (Contributed by NM, 13-Sep-2005)

Ref Expression
Hypothesis rspcv.1 ⊢ x = A → φ ↔ ψ
Assertion rspcva ⊢ A ∈ B ∧ ∀ x ∈ B φ → ψ

Proof

Step Hyp Ref Expression
1 rspcv.1 ⊢ x = A → φ ↔ ψ
2 1 rspcv ⊢ A ∈ B → ∀ x ∈ B φ → ψ
3 2 imp ⊢ A ∈ B ∧ ∀ x ∈ B φ → ψ