Metamath Proof Explorer
Description: Restricted specialization, using implicit substitution. (Contributed by NM, 13-Sep-2005)
|
|
Ref |
Expression |
|
Hypothesis |
rspcv.1 |
⊢ ( 𝑥 = 𝐴 → ( 𝜑 ↔ 𝜓 ) ) |
|
Assertion |
rspcva |
⊢ ( ( 𝐴 ∈ 𝐵 ∧ ∀ 𝑥 ∈ 𝐵 𝜑 ) → 𝜓 ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
rspcv.1 |
⊢ ( 𝑥 = 𝐴 → ( 𝜑 ↔ 𝜓 ) ) |
2 |
1
|
rspcv |
⊢ ( 𝐴 ∈ 𝐵 → ( ∀ 𝑥 ∈ 𝐵 𝜑 → 𝜓 ) ) |
3 |
2
|
imp |
⊢ ( ( 𝐴 ∈ 𝐵 ∧ ∀ 𝑥 ∈ 𝐵 𝜑 ) → 𝜓 ) |