Metamath Proof Explorer


Theorem rspccva

Description: Restricted specialization, using implicit substitution. (Contributed by NM, 26-Jul-2006) (Proof shortened by Andrew Salmon, 8-Jun-2011)

Ref Expression
Hypothesis rspcv.1 x = A φ ψ
Assertion rspccva x B φ A B ψ

Proof

Step Hyp Ref Expression
1 rspcv.1 x = A φ ψ
2 1 rspcv A B x B φ ψ
3 2 impcom x B φ A B ψ