Metamath Proof Explorer


Theorem rspccva

Description: Restricted specialization, using implicit substitution. (Contributed by NM, 26-Jul-2006) (Proof shortened by Andrew Salmon, 8-Jun-2011)

Ref Expression
Hypothesis rspcv.1 ⊢ x = A → φ ↔ ψ
Assertion rspccva ⊢ ∀ x ∈ B φ ∧ A ∈ B → ψ

Proof

Step Hyp Ref Expression
1 rspcv.1 ⊢ x = A → φ ↔ ψ
2 1 rspcv ⊢ A ∈ B → ∀ x ∈ B φ → ψ
3 2 impcom ⊢ ∀ x ∈ B φ ∧ A ∈ B → ψ