Metamath Proof Explorer


Theorem sbccsb

Description: Substitution into a wff expressed in terms of substitution into a class. (Contributed by NM, 15-Aug-2007) (Revised by NM, 18-Aug-2018)

Ref Expression
Assertion sbccsb ( [ 𝐴 / 𝑥 ] 𝜑 ↔ 𝑦 ∈ ⦋ 𝐴 / 𝑥 ⦌ { 𝑦 ∣ 𝜑 } )

Proof

Step Hyp Ref Expression
1 abid ⊢ ( 𝑦 ∈ { 𝑦 ∣ 𝜑 } ↔ 𝜑 )
2 1 sbcbii ⊢ ( [ 𝐴 / 𝑥 ] 𝑦 ∈ { 𝑦 ∣ 𝜑 } ↔ [ 𝐴 / 𝑥 ] 𝜑 )
3 sbcel2 ⊢ ( [ 𝐴 / 𝑥 ] 𝑦 ∈ { 𝑦 ∣ 𝜑 } ↔ 𝑦 ∈ ⦋ 𝐴 / 𝑥 ⦌ { 𝑦 ∣ 𝜑 } )
4 2 3 bitr3i ⊢ ( [ 𝐴 / 𝑥 ] 𝜑 ↔ 𝑦 ∈ ⦋ 𝐴 / 𝑥 ⦌ { 𝑦 ∣ 𝜑 } )