Metamath Proof Explorer


Theorem sbco2vv

Description: A composition law for substitution. Version of sbco2 with disjoint variable conditions and fewer axioms. (Contributed by NM, 30-Jun-1994) (Revised by BJ, 22-Dec-2020) (Proof shortened by Wolf Lammen, 29-Apr-2023)

Ref Expression
Assertion sbco2vv ( [ 𝑦 / 𝑧 ] [ 𝑧 / 𝑥 ] 𝜑 ↔ [ 𝑦 / 𝑥 ] 𝜑 )

Proof

Step Hyp Ref Expression
1 sbequ ( 𝑧 = 𝑤 → ( [ 𝑧 / 𝑥 ] 𝜑 ↔ [ 𝑤 / 𝑥 ] 𝜑 ) )
2 sbequ ( 𝑤 = 𝑦 → ( [ 𝑤 / 𝑥 ] 𝜑 ↔ [ 𝑦 / 𝑥 ] 𝜑 ) )
3 1 2 sbievw2 ( [ 𝑦 / 𝑧 ] [ 𝑧 / 𝑥 ] 𝜑 ↔ [ 𝑦 / 𝑥 ] 𝜑 )