Metamath Proof Explorer


Theorem sbco2vv

Description: A composition law for substitution. Version of sbco2 with disjoint variable conditions and fewer axioms. (Contributed by NM, 30-Jun-1994) (Revised by BJ, 22-Dec-2020) (Proof shortened by Wolf Lammen, 29-Apr-2023)

Ref Expression
Assertion sbco2vv
|- ( [ y / z ] [ z / x ] ph <-> [ y / x ] ph )

Proof

Step Hyp Ref Expression
1 sbequ
 |-  ( z = w -> ( [ z / x ] ph <-> [ w / x ] ph ) )
2 sbequ
 |-  ( w = y -> ( [ w / x ] ph <-> [ y / x ] ph ) )
3 1 2 sbievw2
 |-  ( [ y / z ] [ z / x ] ph <-> [ y / x ] ph )