Metamath Proof Explorer


Theorem sbeqal1i

Description: Suppose you know x = y implies x = z , assuming x and z are distinct. Then, y = z . (Contributed by Andrew Salmon, 3-Jun-2011)

Ref Expression
Hypothesis sbeqal1i.1 ( 𝑥 = 𝑦𝑥 = 𝑧 )
Assertion sbeqal1i 𝑦 = 𝑧

Proof

Step Hyp Ref Expression
1 sbeqal1i.1 ( 𝑥 = 𝑦𝑥 = 𝑧 )
2 sbeqal1 ( ∀ 𝑥 ( 𝑥 = 𝑦𝑥 = 𝑧 ) → 𝑦 = 𝑧 )
3 2 1 mpg 𝑦 = 𝑧