Metamath Proof Explorer


Theorem sbeqal1

Description: If x = y always implies x = z , then y = z . (Contributed by Andrew Salmon, 2-Jun-2011)

Ref Expression
Assertion sbeqal1 ( ∀ 𝑥 ( 𝑥 = 𝑦𝑥 = 𝑧 ) → 𝑦 = 𝑧 )

Proof

Step Hyp Ref Expression
1 sb2 ( ∀ 𝑥 ( 𝑥 = 𝑦𝑥 = 𝑧 ) → [ 𝑦 / 𝑥 ] 𝑥 = 𝑧 )
2 equsb3 ( [ 𝑦 / 𝑥 ] 𝑥 = 𝑧𝑦 = 𝑧 )
3 1 2 sylib ( ∀ 𝑥 ( 𝑥 = 𝑦𝑥 = 𝑧 ) → 𝑦 = 𝑧 )