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SUPPLEMENTARY MATERIAL (USERS' MATHBOXES)
Mathbox for Andrew Salmon
Predicate Calculus
sbeqal1
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Metamath Proof Explorer
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Theorem
sbeqal1
Description:
If
x = y
always implies
x = z
, then
y = z
.
(Contributed by
Andrew Salmon
, 2-Jun-2011)
Ref
Expression
Assertion
sbeqal1
⊢
∀
x
x
=
y
→
x
=
z
→
y
=
z
Proof
Step
Hyp
Ref
Expression
1
sb2
⊢
∀
x
x
=
y
→
x
=
z
→
y
x
x
=
z
2
equsb3
⊢
y
x
x
=
z
↔
y
=
z
3
1
2
sylib
⊢
∀
x
x
=
y
→
x
=
z
→
y
=
z