Metamath Proof Explorer


Theorem sbequ12

Description: An equality theorem for substitution. (Contributed by NM, 14-May-1993)

Ref Expression
Assertion sbequ12 ( 𝑥 = 𝑦 → ( 𝜑 ↔ [ 𝑦 / 𝑥 ] 𝜑 ) )

Proof

Step Hyp Ref Expression
1 sbequ1 ( 𝑥 = 𝑦 → ( 𝜑 → [ 𝑦 / 𝑥 ] 𝜑 ) )
2 sbequ2 ( 𝑥 = 𝑦 → ( [ 𝑦 / 𝑥 ] 𝜑𝜑 ) )
3 1 2 impbid ( 𝑥 = 𝑦 → ( 𝜑 ↔ [ 𝑦 / 𝑥 ] 𝜑 ) )