Metamath Proof Explorer


Theorem sbequ2

Description: An equality theorem for substitution. (Contributed by NM, 16-May-1993) Revise df-sb . (Revised by BJ, 22-Dec-2020) (Proof shortened by Wolf Lammen, 3-Feb-2024)

Ref Expression
Assertion sbequ2 ( 𝑥 = 𝑡 → ( [ 𝑡 / 𝑥 ] 𝜑𝜑 ) )

Proof

Step Hyp Ref Expression
1 dfsbimp ( [ 𝑡 / 𝑥 ] 𝜑 → ∀ 𝑦 ( 𝑦 = 𝑡 → ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) ) )
2 equvinva ( 𝑥 = 𝑡 → ∃ 𝑦 ( 𝑥 = 𝑦𝑡 = 𝑦 ) )
3 equcomi ( 𝑡 = 𝑦𝑦 = 𝑡 )
4 sp ( ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) → ( 𝑥 = 𝑦𝜑 ) )
5 3 4 imim12i ( ( 𝑦 = 𝑡 → ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) ) → ( 𝑡 = 𝑦 → ( 𝑥 = 𝑦𝜑 ) ) )
6 5 impcomd ( ( 𝑦 = 𝑡 → ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) ) → ( ( 𝑥 = 𝑦𝑡 = 𝑦 ) → 𝜑 ) )
7 6 aleximi ( ∀ 𝑦 ( 𝑦 = 𝑡 → ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) ) → ( ∃ 𝑦 ( 𝑥 = 𝑦𝑡 = 𝑦 ) → ∃ 𝑦 𝜑 ) )
8 1 2 7 syl2im ( [ 𝑡 / 𝑥 ] 𝜑 → ( 𝑥 = 𝑡 → ∃ 𝑦 𝜑 ) )
9 ax5e ( ∃ 𝑦 𝜑𝜑 )
10 8 9 syl6com ( 𝑥 = 𝑡 → ( [ 𝑡 / 𝑥 ] 𝜑𝜑 ) )