Metamath Proof Explorer


Theorem sdomdif

Description: The difference of a set from a smaller set cannot be empty. (Contributed by Mario Carneiro, 5-Feb-2013)

Ref Expression
Assertion sdomdif ( 𝐴 ≺ 𝐵 → ( 𝐵 ∖ 𝐴 ) ≠ ∅ )

Proof

Step Hyp Ref Expression
1 relsdom ⊢ Rel ≺
2 1 brrelex1i ⊢ ( 𝐴 ≺ 𝐵 → 𝐴 ∈ V )
3 ssdif0 ⊢ ( 𝐵 ⊆ 𝐴 ↔ ( 𝐵 ∖ 𝐴 ) = ∅ )
4 ssdomg ⊢ ( 𝐴 ∈ V → ( 𝐵 ⊆ 𝐴 → 𝐵 ≼ 𝐴 ) )
5 domnsym ⊢ ( 𝐵 ≼ 𝐴 → ¬ 𝐴 ≺ 𝐵 )
6 4 5 syl6 ⊢ ( 𝐴 ∈ V → ( 𝐵 ⊆ 𝐴 → ¬ 𝐴 ≺ 𝐵 ) )
7 3 6 biimtrrid ⊢ ( 𝐴 ∈ V → ( ( 𝐵 ∖ 𝐴 ) = ∅ → ¬ 𝐴 ≺ 𝐵 ) )
8 2 7 syl ⊢ ( 𝐴 ≺ 𝐵 → ( ( 𝐵 ∖ 𝐴 ) = ∅ → ¬ 𝐴 ≺ 𝐵 ) )
9 8 con2d ⊢ ( 𝐴 ≺ 𝐵 → ( 𝐴 ≺ 𝐵 → ¬ ( 𝐵 ∖ 𝐴 ) = ∅ ) )
10 9 pm2.43i ⊢ ( 𝐴 ≺ 𝐵 → ¬ ( 𝐵 ∖ 𝐴 ) = ∅ )
11 10 neqned ⊢ ( 𝐴 ≺ 𝐵 → ( 𝐵 ∖ 𝐴 ) ≠ ∅ )