Metamath Proof Explorer
Description: Surreal less-than or equal in terms of less-than. Deduction version.
(Contributed by Scott Fenton, 25-Feb-2026)
|
|
Ref |
Expression |
|
Hypotheses |
sled.1 |
⊢ ( 𝜑 → 𝐴 ∈ No ) |
|
|
sled.2 |
⊢ ( 𝜑 → 𝐵 ∈ No ) |
|
Assertion |
sleloed |
⊢ ( 𝜑 → ( 𝐴 ≤s 𝐵 ↔ ( 𝐴 <s 𝐵 ∨ 𝐴 = 𝐵 ) ) ) |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
sled.1 |
⊢ ( 𝜑 → 𝐴 ∈ No ) |
| 2 |
|
sled.2 |
⊢ ( 𝜑 → 𝐵 ∈ No ) |
| 3 |
|
sleloe |
⊢ ( ( 𝐴 ∈ No ∧ 𝐵 ∈ No ) → ( 𝐴 ≤s 𝐵 ↔ ( 𝐴 <s 𝐵 ∨ 𝐴 = 𝐵 ) ) ) |
| 4 |
1 2 3
|
syl2anc |
⊢ ( 𝜑 → ( 𝐴 ≤s 𝐵 ↔ ( 𝐴 <s 𝐵 ∨ 𝐴 = 𝐵 ) ) ) |