Metamath Proof Explorer


Theorem sonr

Description: A strict order relation is irreflexive. (Contributed by NM, 24-Nov-1995)

Ref Expression
Assertion sonr ( ( 𝑅 Or 𝐴 ∧ 𝐵 ∈ 𝐴 ) → ¬ 𝐵 𝑅 𝐵 )

Proof

Step Hyp Ref Expression
1 sopo ⊢ ( 𝑅 Or 𝐴 → 𝑅 Po 𝐴 )
2 poirr ⊢ ( ( 𝑅 Po 𝐴 ∧ 𝐵 ∈ 𝐴 ) → ¬ 𝐵 𝑅 𝐵 )
3 1 2 sylan ⊢ ( ( 𝑅 Or 𝐴 ∧ 𝐵 ∈ 𝐴 ) → ¬ 𝐵 𝑅 𝐵 )