Metamath Proof Explorer


Theorem spcgvOLD

Description: Obsolete version of spcgv as of 25-Aug-2023. (Contributed by NM, 22-Jun-1994) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Hypothesis spcgv.1 ( 𝑥 = 𝐴 → ( 𝜑𝜓 ) )
Assertion spcgvOLD ( 𝐴𝑉 → ( ∀ 𝑥 𝜑𝜓 ) )

Proof

Step Hyp Ref Expression
1 spcgv.1 ( 𝑥 = 𝐴 → ( 𝜑𝜓 ) )
2 nfcv 𝑥 𝐴
3 nfv 𝑥 𝜓
4 2 3 1 spcgf ( 𝐴𝑉 → ( ∀ 𝑥 𝜑𝜓 ) )