Metamath Proof Explorer


Theorem sqrtmuli

Description: Square root distributes over multiplication. (Contributed by NM, 30-Jul-1999)

Ref Expression
Hypotheses sqrtthi.1 𝐴 ∈ ℝ
sqr11.1 𝐵 ∈ ℝ
Assertion sqrtmuli ( ( 0 ≤ 𝐴 ∧ 0 ≤ 𝐵 ) → ( √ ‘ ( 𝐴 · 𝐵 ) ) = ( ( √ ‘ 𝐴 ) · ( √ ‘ 𝐵 ) ) )

Proof

Step Hyp Ref Expression
1 sqrtthi.1 𝐴 ∈ ℝ
2 sqr11.1 𝐵 ∈ ℝ
3 sqrtmul ( ( ( 𝐴 ∈ ℝ ∧ 0 ≤ 𝐴 ) ∧ ( 𝐵 ∈ ℝ ∧ 0 ≤ 𝐵 ) ) → ( √ ‘ ( 𝐴 · 𝐵 ) ) = ( ( √ ‘ 𝐴 ) · ( √ ‘ 𝐵 ) ) )
4 2 3 mpanr1 ( ( ( 𝐴 ∈ ℝ ∧ 0 ≤ 𝐴 ) ∧ 0 ≤ 𝐵 ) → ( √ ‘ ( 𝐴 · 𝐵 ) ) = ( ( √ ‘ 𝐴 ) · ( √ ‘ 𝐵 ) ) )
5 1 4 mpanl1 ( ( 0 ≤ 𝐴 ∧ 0 ≤ 𝐵 ) → ( √ ‘ ( 𝐴 · 𝐵 ) ) = ( ( √ ‘ 𝐴 ) · ( √ ‘ 𝐵 ) ) )