Theorem sqvald

Description: Value of square. Inference version. (Contributed by Mario Carneiro, 28-May-2016)

	Ref	Expression
Hypothesis	expcld.1	⊢ ( 𝜑 → 𝐴 ∈ ℂ )
Assertion	sqvald	⊢ ( 𝜑 → ( 𝐴 ↑ 2 ) = ( 𝐴 · 𝐴 ) )

Proof

Step	Hyp	Ref	Expression
1		expcld.1	⊢ ( 𝜑 → 𝐴 ∈ ℂ )
2		sqval	⊢ ( 𝐴 ∈ ℂ → ( 𝐴 ↑ 2 ) = ( 𝐴 · 𝐴 ) )
3	1 2	syl	⊢ ( 𝜑 → ( 𝐴 ↑ 2 ) = ( 𝐴 · 𝐴 ) )