Metamath Proof Explorer


Theorem sqvald

Description: Value of square. Inference version. (Contributed by Mario Carneiro, 28-May-2016)

Ref Expression
Hypothesis expcld.1 ⊢ φ → A ∈ ℂ
Assertion sqvald ⊢ φ → A 2 = A ⁢ A

Proof

Step Hyp Ref Expression
1 expcld.1 ⊢ φ → A ∈ ℂ
2 sqval ⊢ A ∈ ℂ → A 2 = A ⁢ A
3 1 2 syl ⊢ φ → A 2 = A ⁢ A