Metamath Proof Explorer


Theorem sqcld

Description: Closure of square. (Contributed by Mario Carneiro, 28-May-2016)

Ref Expression
Hypothesis expcld.1 ⊢ φ → A ∈ ℂ
Assertion sqcld ⊢ φ → A 2 ∈ ℂ

Proof

Step Hyp Ref Expression
1 expcld.1 ⊢ φ → A ∈ ℂ
2 sqcl ⊢ A ∈ ℂ → A 2 ∈ ℂ
3 1 2 syl ⊢ φ → A 2 ∈ ℂ