Metamath Proof Explorer


Theorem sqcl

Description: Closure of square. (Contributed by NM, 10-Aug-1999)

Ref Expression
Assertion sqcl ⊢ A ∈ ℂ → A 2 ∈ ℂ

Proof

Step Hyp Ref Expression
1 sqval ⊢ A ∈ ℂ → A 2 = A ⁢ A
2 mulcl ⊢ A ∈ ℂ ∧ A ∈ ℂ → A ⁢ A ∈ ℂ
3 2 anidms ⊢ A ∈ ℂ → A ⁢ A ∈ ℂ
4 1 3 eqeltrd ⊢ A ∈ ℂ → A 2 ∈ ℂ